C

Step 1: Understand the relationship between wavelength and frequency for both light and sound. The speed of light (c) is much greater than the speed of sound (v).
Step 2: The wavelength for any wave can be calculated using the formula:
$$ \lambda = \frac{v}{f} $$
where \(\lambda\) is the wavelength, v is the velocity, and f is the frequency.
Step 3: Since sound travels slower than light, for the same frequency, the wavelength of sound (\(\lambda_s\)) will be greater than that of visible light (\(\lambda_v\)).
Step 4: Therefore, we can conclude that \(\lambda_s > \lambda_v\).
Thus, the correct answer is Option C: \(\lambda_s > \lambda_v\).